Question

number of molecules of C12H22011 that contains 2.35 grams of H

Answer 1

(f) It is given that, Mass of hydrogen = 2.35 g of H Molecular weight of hydrogen = 1.008 g/mol So, the number of moles of hydrogen = (2.35 g / 1.008 g/mol) Number of moles of hydrogen = 2.331 moles of H We have C12H22011 molecule, 1 mole of C12H22O11 molecule contains 22 moles of hydrogen.

So, 1 mole of H can make (1/22) moles of C12H22011 2.331 moles of H = (2.331 / 22) = 0.106 moles of C12H22O11 ... (1) Since, 1 mole = 6.023 x 1023 molecules. Then the number of molecules of C12H22011 = 0.106 x 6.023 x 1023 molecules = 6.39 x 1022 molecules. So, the number of molecules of C12H22O11 = 6.39 x 1022 molecules of C12H22011