24. Calculate the change in AH kJ mol enthalpy (in J per mole of NaHCO (5)...
19. The standard enthalpy of formation for NH (g) is -46.1 kJmolCalculate AH for the reaction 2NH(g)N() 3H.() B 46.1 kJ (A) -92.2 kJ Di 922 kJ (C) 46.1 k 4. Calculate the change in enthalpy (in kJ per mole of CO) for the decomposition of sodium hydrogen carbonate from AH kJmol' NaHCO,(s) Na,CO,(s) H,O() CO (g) the standard enthalpies of formation: 2 NaHCO,(s) Na CO,(s)H0(g) -947.7 -1130.9 -241.8 -393.5 CO(e) (B -818.5 C -1766.2 (D) -3661.6 A 129.2 9....
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g) + 5 O2(g) + 3 CO2(g) + 4H2O(g) Calculate 4, Hº for propane based on the following standard molar enthalpies of formation. molecule CO2(g) H2O(g) 4,Hº (kJ/mol-rxn) -393.5 -241.8
1. The standard enthalpy change for the combustion of mole of propane is -2043.0 kJ. CH_(g) +5 0 (g) →3002(g) + 4H2O(g) Calculate Hº for propane based on the following standard molar enthalpies of formation. molecule CO (9) H2O(g) AH (kJ/mol-rxn) -393.5 -241.8 a. +1407.7 kJ/mol-rxn b. +104.7 kJ/mol-rxn c.-104.7 kJ/mol-rxn d -4190.7 kJ/mol-rxn e. -1407.7 kJ/mol-rxn 2. Which of the following statements is/are CORRECT? 1. If a reaction occurs at constant pressure, 4-AH. 2. The change in energy for...
Principles of Chemical Reactivity: Energy and Chemical Rex Kotz 9e Chapter 5 68. The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CH4(g) +50 (g) 3 CO(g) + 4 H Og) Calculate AHⓇ for propane based on the following standard molar enthalpies of formation. molecule CO/g) H2O(g) AH (kJ/mol-rxn) --393.5 -241.8
Calculate the heat of formation for CaCO3(s) (kJ/mol) given that AH for the following reaction is +178 mole and instander enthalpies of formation: CaCO3(s) - CaO(s) + CO26) AHºf values (kJ/mol): CaO(s) = -635.1, CO2(g) = -393.5 Enter your answer as the nearest whole number with no units.
Calculate the standard enthalpy of formation of CS2() given that AH=-393.5 kJ/mol AHo = -296.4 kj/mol a. C(s) + O2(g) CO2lg) b. S(s) +O2(g). SO2(g) AH = -1073.6 kj/mol C. CS2(I)+302(g) Co2lg) + 2S02(B)
2. Given the following heats of formation, calculate AH for the reaction 2 CO(g) + 5 H2(g) → C2H6 (g) + 2 H2O(g) Compound AH°F (kJ/mol) Compound AH°F (kJ/mol) 52.28 C₂H6 (8) -84.68 C2H4 (8) -393.5 CO2(g) -241.8 H2O(g) -285.9 CO(g) -110.5 H2O(1)
M14. For a particular reaction, the enthalpy change is AH° = +100 kJ/mol and the entropy change is AS° = + 100 J/mol K. What is the equilibrium constant at 300 K?
I need clear solutions and step by step answer. would be helpful to explain what you did too. 46. Using Hess's law, calculate the AH value for the following reaction: (8 marks) FeOce) + CO(g) → Fe(s) + CO2(g) Use these three reactions: Fe,036) + 3CO(g) + 2Fe6) + 3CO2(8) AH= -25.0 kJ 3Fe2O3(s) + CO(g) → 2Fe2O46) + CO2(8) AH = -47.0 kJ Fe30468) + CO(g) + 3FeO (0) + CO2(8) AH = +38.0 kJ Sodium bicarbonate (NaHCO3) is...
6-8 Using the table below, calculate the AH rxn for each of the following equations. Selected Standard Enthalpies of Formation at 25° C (298K) AH (kJ/mol) (kJ/mol Formula AH 0 Silver 92.3 Agis) AgC(3) 0 1270 218 Formula AH (kJ/mol Formula Calcium Ca(s) CI (9) Ca(s) 635.1 HC (G) Caco (s)-1206.9 Hydrogen Hig) Carbon C(graphite) 0 H (9) C(diamond) 1.9 Nitrogen COL) -1105 N19) CO(g) -393.5 NH,(g CH_(9) 74.9 NO(9) CH,OHI) -238.6 Oxygen HỎNG) 133 O.) CS.) 87.9 O (9)...