Perform calculations using Ksp Question For the following equilibrium, if Kp = 5.8 x 10-24, what...

Question

Question

Answer 1

Answer #1

ScF₃ ⇌ Sc³⁺ + 3F^-

Ksp = [Sc³⁺] [3F^-]

Ksp = (s) (3s)³

Ksp = 27s⁴

5.8x10^-24 = 27s⁴

s =6.8078 x10^-7 M

So, molar solubility of scandium fluoride is (s) = 6.8078 x10^-7 M

Answer 2

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