Lets number the reaction as 0, 1, 2 from top to bottom
required reaction should be written in terms of other
reaction
This is Hess Law
required reaction can be written as:
reaction 0 = +2 * (reaction 1) -1 * (reaction 2)
So, ΔHo rxn for required reaction will be:
ΔHo rxn = +2 * ΔHo rxn(reaction 1) -1 * ΔHo rxn(reaction 2)
= +2 * (-74.9) -1 * (-84.5)
= -65.3 KJ
Answer: -65.3 KJ
Now write down the manipulated reactions nu uiel CUIT 2) Consider the reaction of methane with...
Now write down the manipulated reactions mu unsbt nol htemoldo ncb bneo r bn 0oY ob u 2) Consider the reaction of methane with hydrogen to give methane to abte emc CHe (g)+ H2 (g)2CHa (g) Calculate the value for AH for this reaction given the following thermochemical equations C (s)+2H2 (g) CHa (g) AH =-74.9 kJ 2C (s)+3H2 (g)C2Hs (g) AH = -84.5 kJ bages S ulate the AH° for the following.co ction
The direct reaction of methane (CH) with oxygen to give carbon monoxide is hard to accomplish without also producing carbon dioxide. However, we can use a Hess's law calculation to calculate AH,anyway. Calculate AH in kJ for the following reaction from the thermochemical equations given. 35. 2CO(g) + 4H2O() 2CH&(g) +302(g) Use the following thermochemical equations: AH-221.08 kJ 2CO(g) (1) 2C(s)+O2(g) AH=-890.4 kJ CH&g)+202(g) CO2(g)+ 2H20() (2) AH -393.51 kJ CO2(g) C(s)+O2(g) (3)
717)Use the reactions below to calculate the standard change in enthalpy for the reaction of methane (CH4) with chlorine to form chloroform (CHC13) and hydrochloric acid: CH4(g) + 3Cl2(g) → CHCI3(g) + 3HCI(g) Reaction 1: HCI(g) → H2(g) + 2Cl2(g) AH° = +92.3 kJ Reaction 2: CH4(g) → C(s) + 2H2(g) AH° = +74.8 kJ Reaction 3: C(s) + 3H2(g) + 3/2Cl2(g) →CHCl3(g) AH° = -103.1 kJ x a. +270.2 kl b. +248.6 kJ PC. +64.0 kJ -120.6 kJ -305.2...
What is the enthalpy of the following reaction: CH4(g) + NH3(g) à HCN(g) + 3H2(g) Use the data from the following three reactions: N2(g) + 3H2(g) à 2NH3(g) DrH° = -91.8 kJ C(s) + 2H2(g) à CH4(g) DrH° = -74.9 kJ H2(g) + 2C(s) + N2(g) à 2HCN(g) DrH° = +270.3 kJ 437 kJ 150 kJ 391 kJ 287 kJ 256 kJ
DaC. NUL20 1) Find AH, for the reaction 2H2(g) + 2C(s) + O2(g) → C2H5OH(I), using the following thermochemical data. For Hess's Law, rewrite equations to find out AH. C2H5OH (1) +2 02 (g) → 2 CO2 (g) + 3H20 (1) AH = -875.J C(s) + O2(g) → CO2 (g) AH = -394,51 kJ H2(g) + 12 02 (g) → H20 (1) AH = -285.8 kJ
3. Use the thermochemical equations shown below to determine the enthalpy for the reaction for CH3COOH()2C(s) +2H2(g) + O2(g) 2CO2(g)+ 2H2OI)CH3COOH(l) + 202(B) AH 3484 kJ C(s)+ O2(g)CO2(g) AH= -1576 kJ AH= -2288 kJ 2H2O(I) 2H2(g)+ O2(g)
Question 36 of 50 Submit Using the equations N2(g) + 3 H2(g) - 2 NH; (g) AH = -91.8 kJ/mol C(s) + 2 H (g) – CH2 (g) AH° = -74.9 kJ/mol H2 (g) + 2c(s) + N2 (g) - 2 HCN (g) AH = 270.3 kJ/mol Determine the enthalpy for the reaction CH, (g) + NH4 () – HCN (g) + 3 H2(g). kJ/mol 1 2 3 C +/- : 0 x 100
3. Calculate the enthalpy of formation of carbon dioxide in the following reaction: C(s) + O2 (g) – CO2 (g) 213 Use the following equations: a) H20 (0) -- H2(g) + 103() AH',- +285.8 kJ/mol b) CH. (g) -2C (s) + 3H2(g) AH:- +84.7 kJ/mol c) 2CO2(g) +3H() - CH.(g) + (7/2) O, (g) AH,- +1560.7 kJ/mol
Review Problem 6.086 Given the following thermochemical equations, 2Cu + S(s) - Cu2S(s) AH° = -79.5 kJ S(s) + O2(g) → SO2(9) AH = -297 kJ Cu2S(s) + 202(g) → 2CụO(s) + SO2(g) AH° = -527.5 kJ calculate the standard enthalpy of formation (in kilojoules per mole) of Cuo(s). AH°(Cuo(s)) - kJ/mol The number of significant digits is set to 3; the tolerance is +/-2% Show Work is REQUIRED for this question: Open Show Work Review Problem 6.087 Given the...
The overall reaction to produce chloroform from methane is CH4(g) + 3Cl2(g) ---> CHCl3(l) + 3HCl(g). Use the following intermediate reactions to calculate the enthalpy of the reaction, Hrxn. 1/2 H2(g) + 1/2 Cl2(g) ---> HCl(g) Hrxn = -92.3 kj C(s) + 2H2(g) ----> CH4(g) Hrxn = -74.8 kj C(s) + 1/2 H2(g) + 3/2 Cl2(g) ----> CHCl3(l) Hrxn = -134.5 kj