Question

Question 16 of 20 Determine the energy of a photon with a wavelength of 290 nm. 1 2 3 4 5 6 7 8 9 + 0 x 100

Answer 1

Energy of a photon,

E = hc/

where,

h = Planck's constant = 6.626 x 10^-34 J.s

c = speed of light in vacuum = 3 x 10⁸ m/s

= wavelength of light = 290 nm = 290 x 10^-9 m      ($\because$ 1 nm = 10^-9 m)

Hence the energy of the photon,

E = (6.626 x 10^-34 J.s)(3 x 10⁸ m/s)/(290 x 10^-9 m)

   = 6.85 x 10^-19 J