Question

Calculate the theoretical and percent yield given: 0.648 g of isopentyl alcohol and 1.58 g of acetic acid. This was found to produce 0.351 g of iso-pentyl acetate + H2O. Acetic acid was in excess. This is a Fischer Esterification problem.

Answer 1

gsopentyl alcohol mol. weight = 88.15 g/mol sopentyl acetate mot weight : 130.19 g/mol 88.15 g of gsopentyl alcohol Imole g. 18. 16 more Given 8.648 g - 0.648 mole = 0.0073511 mole 88.15 130.19 g of gsopentyl acetate = 1 mole I g = mole 130.19 0.351g = 0.351 = 0.0097 mole 130.19 Theoritically I mole of geopentyl alcohol will give I mole of geopentyl acetate. so, theoritical yield from 0.6489(0.0073511 mole) of Isopentyl alcohol should be 0.0073511 mole of gsopentul attor gsopentyl acetate.

for gsopentyl acetate theoretical yield actual yield = 0.0073 511 mole 0.0027 mole Y yield yield actual x 100 theoritical yield 0.002 ] 0.0073511 X 100 = 36.73 pervent yield 36-73%