Question

If 4.46 g of acetic acid and 2.19 g of isopentyl alcohol are used in the reaction, what is the limiting reagent? What is the theoretical yield? What is the percent yield if 2.50 g of isopentyl acetate are obtained? (please show all calculations!!!)

Answer 1

this ale Reaction of aceste acel and infolyt olchel. ОИ - 240 3 X 2 mom. THO a meles of acetie a cid= _mass = 446J molare mass 60g/mol = 7434103 mol o) males of isopentyl = 21 g = 24.83 x 10 mot Step® finding Liriking veogent- a) fi male tee Cofficient of activacidë moles Cofficient - 740 34103 mol - 74.34103 b) mole per officient of isopentyl = moly cofficient = 24.83 X10 mal = 24.8 x 10 mod & so. Vinę ding keagent = isopentyl. . Cauwe, mole por coff oof isoperlyl 2 mols pey coff- acetic acid

atteply find meels of so hentyl acetate applied POAC 7 males of isopeutyl acetate, moles of dopoutayl Coffreien moles of isopentyl acetates - 24.83 4102 mol Cofficient. mass of isopentyl acetate 24083 610-3 Moloumass mass = 24+881037 130.2 makes - 302339 (Theortical yeëld) see step m find % geild. % Jeild = actual mass - x 100 Theoretical mars 205 g x 100 = 77.33% 3.2339 Thank you, May it help you . .