A ball is thrown vertically upwards at 29.4 m/s. For its complete trip (up and back down to the starting position), its average speed is:
a. not given.
b. 9.80 m/s.
c. 14.7 m/s.
d. 4.90 m/s.
Given that
Initial velocity of ball,u = 29.4 m/s
We know that
acceleration due to gravity = 9.8
v at maximum height = 0
Then for maximum height ,
0 = 29.42 + 2 (-9.8) h
0 = 864.36 - 19.6 h
h = 44.1 m
Now for time
v = u + at
=> 0 = 29.4 + (-9.8) t
=> t = 3 s
now as total distance = 2 h = 2 (44.1) = 88.2 m
and total time = 2 t = 2(3) = 6 sec
then average velocity = Total distance/total time = 88.2/6 = 14.7 m/s
Average velocity = 14.7 m/s
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