What is the Ka of a weak acid (HA) if equilibrium concentrations are [H3O+] = [A-] = 6.1 x 10-4 M , [HA] = 0.25 M
What is the Ka of a weak acid (HA) if equilibrium concentrations are [H3O+] = [A-]...
What is the Ka for an acid HA, if the equilibrium concentrations are [HA]=0.822 M, [H3O+]=1.15×10−4 M, and [A−]=1.15×10−4 M?
The weak acid HA has a Ka of 4.5×10−6. If a 1.4 M solution of the acid is prepared, what is the pH of the solution? The equilibrium expression is: HA(aq)+H2O(l)⇋H3O+(aq)+A−(aq)
A 0.050 M solution of a weak monoprotic acid, HA, has [H3O+] = 3.8 x 10-5. What is the value of Ka for this acid? 2.6 x 10-11 2.9 x 10-8 7.5 x 10-3 7.0 x 10-8 7.0 x 10-7
What is the pH of a 0.44 M solution of a weak acid HA, with a Ka of 3.19×10−12? The equilibrium expression is: HA(aq)+H2O(l)⇌H3O+(aq)+A−(aq)
A monoprotic weak acid, HA, dissociates in water according to the reaction HA(aq) + H2O(1) H2O+(aq) + A-(aq) The equilibrium concentrations of the reactants and products are [HA] = 0.250 M, H,O+] = 2.00 x 10-4 M, and [A-] = 2.00 x 10-4 M. Calculate the Ka value for the acid HA. Ka = 6.79588
ASAP! What is Ka for the weak acid, HA, if a 0.020 M solution of the acid has a pH of 3.29 at 25ºC? a. 5.1 × 10-2 b. 6.9 × 10-2 c. 2.6 × 10-4 d. 1.3 × 10-5 e. 1.0 × 10-6 What is the conjugate acid of H2PO4–(aq)? a. H3O+ b. H3PO4 c. HPO42– e. PO43–
A monoprotic weak acid, HA, dissociates in water according to the reaction HA(aq)↽−−⇀H+(aq)+A−(aq) The equilibrium concentrations of the reactants and products are [HA]=0.280 M, [H+]=2.00×10−4 M, and [A−]=2.00×10−4 M. Calculate the value of pKa for the acid HA.
From the equilibrium concentrations given, calculate Ka for each of the weak acids and Kb for each of the weak bases. (a) HCH3CO2: [H3O+ ] = 1.53 ✕ 10−3 M, [CH3CO2− ] = 1.53 ✕ 10−3 M, [HCH3CO2] = 0.138 M (b) ClO−: [OH − ] = 2.51 ✕ 10−4 M, [HClO] = 2.51 ✕ 10−4 M, [ClO− ] = 0.250 M
The ionization constant of a very weak acid, HA, is 8.8x10-9. Calculate the equilibrium concentrations of H2O, A', and HA in a 0.040 M solution of the acid. Determine the concentrations of all species at equilibrium and the solution pH. [H30]= mol/L [A] = moll mol/L [HA] = pH =
A diprotic acid, H,A, has acid dissociation constants of Ka molar concentrations of H,A, HA-, and A2- at equilibrium for each of the solutions 1.42 x 10-4 and Ka2 = 4.07 x 1012. Calculate the pH and = A 0.210 M solution of H,A H2A] = pH HA- A2- М М A 0.210 M solution of NaHA HA pH= М