A 0.050 M solution of a weak monoprotic acid, HA, has [H3O+] = 3.8 x 10-5. What is the value of Ka for this acid?
2.6 x 10-11
2.9 x 10-8
7.5 x 10-3
7.0 x 10-8
7.0 x 10-7
A 0.050 M solution of a weak monoprotic acid, HA, has [H3O+] = 3.8 x 10-5. What is the value of Ka for this acid? 2.6 x...
A weak acid, HA, is a monoprotic acid. A solution that is 0.250 M in HA has a pH of 1.890 at 25°C. HA(aq) + H2O(l) ⇄ H3O+(aq) + A-(aq) What is the acid-ionization constant, Ka, for this acid? What is the degree of ionization of the acid in this solution? Ka = Degree of ionization =
ASAP! What is Ka for the weak acid, HA, if a 0.020 M solution of the acid has a pH of 3.29 at 25ºC? a. 5.1 × 10-2 b. 6.9 × 10-2 c. 2.6 × 10-4 d. 1.3 × 10-5 e. 1.0 × 10-6 What is the conjugate acid of H2PO4–(aq)? a. H3O+ b. H3PO4 c. HPO42– e. PO43–
39. A solution of a weak monoprotic acid, HA (0.50 M), and its potassium salt, KA (0.75 M), has a measured pH = 4.88. What is the value of Ka for this acid?
What is the pH of a 6.85 × 10−3 M weak acid solution, HA, if Ka = 4.5 × 10−6? Group of answer choices 1.2 4.8 9.1 3.8 6.5 What is the pOH of 4.50 × 10−4M HBr? Group of answer choices 10.7 6.7 1.7 12.3 3.3 What is the pH of a 9.67 × 10−3M solution of NaOH? Group of answer choices 13.0 4.6 12.0 9.4 2.0 A 6.5 × 10-2 M solution of a weak acid, HA, has...
The weak acid HA has a Ka of 4.5×10−6. If a 1.4 M solution of the acid is prepared, what is the pH of the solution? The equilibrium expression is: HA(aq)+H2O(l)⇋H3O+(aq)+A−(aq)
What is the Ka of a weak acid (HA) if equilibrium concentrations are [H3O+] = [A-] = 6.1 x 10-4 M , [HA] = 0.25 M
The Ka of a weak monoprotic acid is 1.55 x 10-5. What is the pH of a 0.0813 M solution of this acid? pH
1. A weak monoprotic acid has molar mass 180 g/mol. When 1.00 g of this acid is dissolved in enough water to obtain a 300 mL solution, the pH of the resulting solution is found to be 2.62. What is the value of Ka for this acid? 2. A weak monoprotic acid has pKa = 3.08. Calculate the percent ionization of a 0.35 M solution of this acid. 3. Calculate the pH of a solution that is 0.050 M in CH3COOH...
You make a 0.1 M solution with acid HA, a monoprotic acid. The Ka for this acid is 1.0E-8. If HA is mixed with a 50 M NaCl solution (no common ions with HA), determine the percent ionization of HA. So I calculated that the ionic strength of the solution is equal to 0.2 and found the activity coefficent to be 0.7469. When I plugged in the values into the Ka=(activity of A- * activity of H3O+)/activity of HA equation,...
A buffer solution is composed of 0.380 M HA, a weak monoprotic acid, and 0.760 M NaA, the sodium salt of the acid. The solution has a pH of 4.10. What is the Ka of the weak acid, HA? tks!!!!!!!!!!!!!