I have used Excel to solve the above problem. I will attach the outputs along with the solution.
a)
SUMMARY OUTPUT | ||||||||
Regression Statistics | ||||||||
Multiple R | 0.604018 | |||||||
R Square | 0.364838 | |||||||
Adjusted R Square | 0.258977 | |||||||
Standard Error | 4.977081 | |||||||
Observations | 8 | |||||||
ANOVA | ||||||||
df | SS | MS | F | Significance F | ||||
Regression | 1 | 85.37198 | 85.37198 | 3.446402 | 0.112778 | |||
Residual | 6 | 148.628 | 24.77134 | |||||
Total | 7 | 234 | ||||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | |
Intercept | 85.42029 | 6.481016 | 13.18008 | 1.18E-05 | 69.56181 | 101.2788 | 69.56181 | 101.2788 |
X Variable 1 | 3.63285 | 1.956882 | 1.856449 | 0.112778 | -1.15547 | 8.421167 | -1.15547 | 8.421167 |
Revenue=85.42 + 3.6 TV Adv is the estimated regression equation.
b)
SUMMARY OUTPUT | ||||||||
Regression Statistics | ||||||||
Multiple R | 0.702543 | |||||||
R Square | 0.493567 | |||||||
Adjusted R Square | 0.290994 | |||||||
Standard Error | 4.868373 | |||||||
Observations | 8 | |||||||
ANOVA | ||||||||
df | SS | MS | F | Significance F | ||||
Regression | 2 | 115.4947 | 57.74736 | 2.436489 | 0.182518 | |||
Residual | 5 | 118.5053 | 23.70106 | |||||
Total | 7 | 234 | ||||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | |
Intercept | 74.03494 | 11.92395 | 6.208926 | 0.001583 | 43.38344 | 104.6864 | 43.38344 | 104.6864 |
X Variable 1 | 5.077852 | 2.303655 | 2.204259 | 0.078671 | -0.84388 | 10.99959 | -0.84388 | 10.99959 |
X Variable 2 | 2.739152 | 2.429701 | 1.127362 | 0.310765 | -3.50659 | 8.984898 | -3.50659 | 8.984898 |
Revenue = 74.03 + 5.08 TV Adv + 2.74 NV Adv is the estimated regression equation.
c) NO. The estimated regression equation coefficient for television advertising expenditures are different in part (a) and part (b).
d) Revenue = 74.03 + 5.08 (3.6) + 2.74 (1.6) = 96.702.
Hence, the weekly gross revenue for a week when $3.6 thousand is spent on television advertising and $ 1.6 thousand is spent on newspaper advertising is $96.70 thousand.
Use computer software packages, such as Minitab or Excel, to solve this problem. The owner of...
Use computer software packages, such as Minitab or Excel, to solve this problem. The owner of Showtime Movie Theaters, Inc., would like to predict weekly gross revenue as a function of advertising expenditures. Historical data for a sample of eight weeks follow. Weekly Gross Revenue ($1,000s) Television Advertising ($1,000s) Newspaper Advertising ($1,000s) 1.5 4.2 2.5 a. Develop an estimated regression equation with the amount of television advertising as the independent variable (to 1 decimal). Revenue = + TVAdv b. Develop...
Use computer software packages, such as Minitab or Excel, to solve this problem, The owner of Showtime Movie Theaters, Inc., would like to predict weekly gross revenue as a function of advertising expenditures. Historical data for a sample of eight weeks follow Weekly Gross Revenue ($1,000s) Television Advertising ($1,000s) Newspaper Advertising ($1,000s) 1.5 2.0 2.0 2.5 3.0 a. Develop an estimated regression equation with the amount of television advertising as the independent variable (to 1 decimal) Revenge = + TV...
Use computer software packages, such as Minitab or Excel, to solve this problem. The owner of Showtime Movie Theaters, Inc., would like to predict weekly gross revenue as a function of advertising expenditures. Historical data for a sample of eight weeks follow. Weekly Gross Revenue ($1,000s) Television Advertising ($1,000s) Newspaper Advertising ($1,000s) 1.5 105 2.5 a. Develop an estimated regression equation with the amount of television advertising as the independent variable (to 1 decimal). Revenue = TV Adv b. Develop...
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