Homework Answers
Part 1 : 59.45 % C in C22H24N2O8
Part 2 : 5.44 % H in C22H24N2O8
Part 3 : 6.30 % N in C22H24N2O8
Part 4 : 28.80 % O in C22H24N2O8
Explanation
Part 1
molar mass C22H24N2O8 = 444.4346 g/mol
mass C in C22H24N2O8 = 12 * (molar mass C)
mass C in C22H24N2O8 = 12 * (12.0107 g/mol)
mass C in C22H24N2O8 = 144.1284 g/mol
mass % C = (mass C in C22H24N2O8 / molar mass C22H24N2O8) * 100
mass % C = (144.1284 g/mol / 444.4346 g/mol) * 100
mass % C = (0.5945) * 100
mass % C = 59.45 %
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