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enzyme has a molar mass of 30 kilodatons. From this information, calculate Keat for this enzyme-catalyzed reaction both with
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Answer #1

From the data given above the y- intercept gives the reciprocal value of Vmax .Here from the graph it is 2.

Therefore,

2 тат

Vmат — 0.5 тат.

Kcat E0.5 тат

Since here the unit of Vmax is not given,we can assume it to be as M/min.

In that case

0.5M таr тат 1min

Let us suppose , [E]=0.5M then Kcat becomes 1 min-1.

From the nature of the graph it is "Fully Competitive Inhibition".

Below is the nature of the graphs for different types of inhibition.

1 [I 0 V 1 Vmax -1 1 Км(1 + [S] 1 KM Fully Competitive Inhibition

1 [I] 0 1 Vmax 1 Vmax 1 [S] Fully Non-Competitive Inhibition

1 V = 0 I] 1+ KJ 1 Vimax 1 S] -1 Км(1 + ) UnCompetitive Inhibition

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