Question

How many grams of calcium chloride were used if 2.498 grams of calcium oxalate monohydrate were produced, assuming a 100% yield. This means all of the calcium chloride was converted to calcium oxalate monohydrate. Report your answer to 3 decimal places in grams.

Answer 1

Solution

molar mass of calcium chloride (CaCl₂)= 110.98 g/ mol

calcium oxalate monohydrate = 2.498 g

molar mass of calcium oxalate monohydrate = 146.11 g/mol

now number of moles of calcium oxalate monohydrate = weight of calcium oxalate monohydrate / molar mass

number of moles of calcium oxalate monohydrate = 2.498 g / 146.11 g/mol

number of moles of calcium oxalate monohydrate = 0.0171 moles

Molar ratio of calcium oxalate monohydrate & calcium chlorideis 1:1 (i.e. 1 mole of calcium chloride produce 1 mole calcium oxalate monohydrate)

Hence moles of calcium chloride = number of mole of calcium oxalate monohydrate

Mass of calcium chloride = number of moles of calcium chloride x molar mass of CaCl₂

Mass of calcium chloride = 0.0171 mole x 110.98 g / mol

Mass of calcium chloride = 1.90 g

Here 1.90 g of calcium chloride is used to produce 2.498 g of calcium oxalate monohydrate.