4 F
5 C
6 J
7 K
8 B
9 D
10 G
NMR worksheet: H-1 (proton) NMR -COOH کد 11 وه اسط .)= X For each compound: 4....
For each compound: 1. Determine the number of equivalent hydrogens - number of different signals 2. Determine the splitting pattern of each signal 3. Sketch a possible spectrum 4. Then try to match the compound to the correct NMR spectrum er w t & You We were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this imageNMR worksheet H-1 (proton NMR D for each compound 1. Debamia the number of equivalent hydropens number...
-COOH 811-812 O x - - .o. -C For each compound: 1. Determine the number of equivalent hydrogens - number of different signals 2. Determine the splitting pattern of each signal 3. Sketch a possible spectrum 4. Then try to match the compound to the correct NMR spectrum ļ wt ♡ na 1CECH PPM
NMR worksheet: C-13 NMR - || - | |-- alkanes Ester C=0 approx. 170 - 180 ppm For each compound: 1. Determine the number of equivalent carbons 2. Predict and sketch the location of the peaks 3. Then try to match the compound to the correct NMR spectrum بز به م . . We were unable to transcribe this image
Match the compound with this proton NMR spectrum. 12 10 00 PPM OH OH H IV OA! B.11 Oc! ODV E. none of these
2. (10 points) The proton NMR spectrum of a compound with a formula CsH100 is shown. The decoupled carbon-13 and DEPT results are show in the table. The infrared spectrum shows a broad peak at about 3340cm and a medium peak about 1650 cm. Draw a structure for this compound and explain the data. Decoupled "CNMR, DEPT- DEPT-90 ppm 135 22.2 positive no peak 40.9 negative no peak 60.2 negative no peak 112.5 negative no peak 142.3 no peak no...
(References The proton NMR spectrum for a compound with the formula C,H,O is shown below along with the spectral data in tabular form. (It may be necessary to expand (zoom) some of the 'H signals to view spin-spin splitting details.) Intensity 258 $ $ 488 14 13 12 11 10 9 8 7 6 5 4 3 Chemical Shift (oppm 2 1 0 . Reproduced with permission from Sim. Aldri Ca LLC The IH signal at 2.15 ppm is an...
I have an proton NMR for a compound that I believe to be Salicylic Acid. It has major peaks at 11.0 ppm as well as around 10.5 ppm. Both peaks are broad singlets indicating that they should be -OH peaks. However, the typical Phenol has a peak around 5-6 ppm. Could it be possible that the aromatic ring and carbonyl group from the carboxylic acid influenced the phenol group enough to shift it that far downfield?
NMR worksheet: C-13 NMR somatic cuct c-a.c-- - --- LLLLLLLLLLLLLLLLLLLLLLL Ester C=O approx. 170-180 ppm For each compound: 1. Determine the number of equivalent carbons 2. Predict and sketch the location of the peaks 3. Then try to match the compound to the correct NMR spectrum 3. & Lond. 6. B O DO do 1howo 10 120109
-NMR and H-NMR – label both unambiguously and clearly illustrate that you understand proton and carbon environments (i.e. Draw out the skeletal structure of the compound, label the H’s a, b, c’s and the C’s 1, 2, 3’s. Then label all signals on the NMR with those corresponding letters/numbers accordingly.). We were unable to transcribe this imageWe were unable to transcribe this imageC7H140 CDCl3 240 200 QE-300 180 129 100
The proton NMR spectrum for a compound with the formula C,H,O, is shown below along with the spectral data in tabular form. (It may be necessary to expand (zoom) some of the 'H signals to view spin-spin splitting details.) This compound exhibits strong infrared absorption at 1727 and 1195 em plus a medium intensity band at 1637 cm! 13C NMR Data 'H NMR Data Proton Shift Relative Area Normal Carbon DEPT-135 DEPT-90 14.2 Positive No peak 60.4 Negative No peak...