There is no prior information about the proportion of Americans who support the gun control in 2018. If we want to estimate 92% confidence interval for the true proportion of Americans who support the gun control in 2018 with a 0.24 margin of error, how many randomly selected Americans must be surveyed?
When no prior estimate for proportion is specified then p = 0.50
Sample size = Z2/2 * p( 1 - p) / E2
= 1.75072 * 0.50 * 0.50 / 0.242
= 13.3
n = 14 (Rounded up to nearest integer)
There is no prior information about the proportion of Americans who support the gun control in...
There is no prior information about the proportion of Americans who support the gun control in 2018. If we want to estimate 95% confidence interval for the true proportion of Americans who support the gun control in 2018 with a 0.2 margin of error, how many randomly selected Americans must be surveyed? (Round up your answer to nearest whole number)
There is no prior information about the proportion of Americans who support gun control in 2019. If we want to estimate 93% confidence interval for the true proportion of Americans who support gun control in 2019 with a 0.18 margin of error, how many randomly selected Americans must be surveyed?
There is no prior information about the proportion of Americans who support gun control in 2019. If we want to estimate 97% confidence interval for the true proportion of Americans who support gun control in 2019 with a 0.27 margin of error, how many randomly selected Americans must be surveyed? Answer:
There is no prior information about the proportion of Americans who support free trade in 2019. If we want to estimate a 98% confidence interval for the true proportion of Americans who support free trade in 2019 with a 0.21 margin of error, how many randomly selected Americans must be surveyed? Answer
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