A survey of 2,500 U.S. citizens yielded 1,600 who are in favor of gun control legislation....
A survey of 2,500 U.S. citizens yielded 1,600 who are in favor of gun control legislation. Estimate the proportion of all Americans who are in favor of gun control legislation using a 95% confidence interval.
Homework Answers
Sample proportion = x/n = 1600/2500 = 0.64
For 95% confidence, z = 1.96
Hence,
95% confidence interval will be:
(0.6212, 0.6588)
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A survey of 2,500 U.S. citizens yielded 1,600 who are in favor
of gun control legislation....
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Many people think that a national lobby's successful fight against gun control legislation is reflecting the will of a minority of Americans. A previous random sample of 4000 citizens yielded 2250 who are in favor of gun control legislation. How many citizens would need to be sampled if a 95% confidence interval was desired to estimate the true proportion to within 2%? Select one: a. 2498 b. 2401 c. 2209 d. 2364
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