Question

A conducting rod of mass m and resistance R, slides with no friction on an horizontal rail of width l and negligible resistance. At t=0, the rod passes O with a velocity v0. The rail is closed from one side only, so that the rod actually forms a closed circuit. A constant magnetic field B is present everywhere, perpendicular to the plane of the rail. v0, m , l, R and B are given?

Which of the following statements is true? Select one: The rod will continue to move at vo C. The rod will stop at x = The rod will stop at x = 4,豐, but only if the magnetic field is directed out of the screen, not if it is directed into the screen. The rod will stop at x = 4 The rod will continue to move at u = vo

$x=\frac{v_{0}mR}{l^2B^2}$ OR $x=\frac{4v_{0}mR}{\pi l^2B^2}$

Answer 1

Cnrent throug h the rod is 2 Force on the γ0d. chan .fl 久 つく atve し43-/ m p. mp the rod sh ould stop