The rate of formation of NO(g) in the reaction NOBr(g)→ NO(g) + Br2 (g) is found to be 1.6 × 10–4 M/s. Find the rate of rate of reaction and rate of consumption of NOBr.
The rate of formation of NO(g) in the reaction NOBr(g)→ NO(g) + Br2 (g) is found...
The reaction 2NOB → 2NO+ Br2 exhibits the rate law Rate = k[NOBr] = A[NOBr) A: where k = 1.0 x 10-5 M-1.5 at 25° C. This reaction is run where the initial concentration of NOBT ([NOBr]) is 1.00 x 10- M. Calculate the [NO] (M) after 3.6 hours have passed. Report your answer to two significant figures. Answer:
For the decomposition of nitrosyl bromide at 10 °C 2 NOBr(g)2NO) +Br2(g) the average rate of disappearance of NOBr over the time period from t-0s to t 6.48 s is found to be 2.24 102Ms What is the average rate of appearance of Br2 over the same time period? Submit Show Anproach Show Tutor Steps Sulbmit Answer 5 iten attempts remaining
for the reaction 2NOBr(g)---- 2NO(g)+Br2(g) the rate of the reaction -2.3 mol NOBr/L/h when the initial NOBr concentration was 6.2 mol NoBr/L. what is the rate constant of the reaction. Please help:) 52. For the reachon ZNO Brly) - 2Noig) + Brela) the rate of the reaction was -23 mol NoBrilh when the inihol NOBY Coventration was 2 mol NOBYL Wat is the rate constant of the reaction?
ate data for the reaction: 2 NO (g) + Br2 (g) → 2 NOBr (g) n below Fl. M 0.100 0.200 0.300 0.300 INH,J.M Initial Rate, M/min Experiment 2 4 0.200 0.200 0.150 0.050 0400mm 0.80 2.55 0.850 rate law for this reaction, and determine the value of K. Show reasoning! (8 points)
At 141 oC, Keq = 0.00830 for the reaction: NO(g) + 1/2 Br2(g) NOBr(g) (a) What is the value of Keq for the reaction NOBr(g) NO(g) + 1/2 Br2(g)? Keq = . (b) What is the value of Keq for the reaction 2 NO(g) + Br2(g) 2 NOBr(g)? Keq = . (c) What is the value of Keq for the reaction 2 NOBr(g) 2 NO(g) + Br2(g)? Keq = .
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentration of 0.86 M, calculate the concentration of NOBr after 89 s. M
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentration of 0.86 M, calculate the concentration of NOBr after 59 s.
2NO(g) + Br2(g) = 2NOBr(g) Experiment [NO-] (M) [Br2] (M) Initial Rate (M s-1) 1 0.10 0.20 24 2 0.25 0.20 150 3 0.10 0.50 60 4 0.35 0.50 735 1.) Determine the rate law equation for the reaction. 2.) What is the overall order of the reaction? 3.) What are the value and the units of the rate constant, k? 4.) Write the expression to show how is the rate of disappearance of bromine, Br2, related to the rate...
What is the rate of disappearance of Br2 when [NO]= 8.6×10−2 M and [Br2]= 0.31 M ? Express your answer using two significant figures. The rate of disappearance of Br2 is half the rate of appearance of NOBr, and the initial problem was: Consider the gas-phase reaction between nitric oxide and bromine at 273 ∘C 2NO(g)+Br2(g)→2NOBr(g). The following data for the initial rate of appearance of NOBr were obtained: Experiment [NO](M) [Br2](M) Initial Rate of Appearance of NOBr(M/s) 1 0.10...
In a study of the decomposition of nitrosyl bromide at 10 °C NOBr—+NO+ Br2 the concentration of NOBr was followed as a function of time. It was found that a graph of 1/[NOBr] versus time in seconds gave a straight line with a slope of 1.27 m?s and a y-intercept of 3.98 M? Based on this plot, the reaction is order in NOBr and the rate constant for the reaction is M?? In a study of the decomposition of hydrogen...