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A block of mass m1 = 1.65 kg and a block of mass m2 = 6.15 kg are connected by a massless string over a pulley in the shape o

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Answer #1

A)

Acceleration, a = (m2 g sin(theta) - u m2g cos(theta) - u m1g)/(m1 + m2 + M/2)

a = [(6.15 x 9.8 sin(30)) - (0.36 x 6.15 x 9.8 cos(30)) - (0.36 x 1.65 x 9.8)]/(1.65 + 6.15 + 10/2)

a = 0.43 m/s^2

B)

T1 = m1a + um1g

T1 = (1.65 x 0.43) + (0.36 x 1.65 x 9.8) = 6.53 N

C)

T2 = m2g sin(theta) - um2g cos(theta) - m2a

T2 = (6.15 x 9.8 sin(30)) - (0.36 x 6.15 x 9.8 x cos(30)) - (6.15 x 0.43) = 8.70 N

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