Chapter 22, Problem 014 In the figure particle 1 of charge o, field of the particles...

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Answer 1

Answer #1

let that point is to the right of q2 at a distance of d

at that point, electric field due to q1 must be equal to electroc field due to q2

k q1 / ( L + d) ^2 = k q2 / d^2

sqrt ( q1/q2) = L/d +1

sqrt ( 5.32 / 1.22) = L/d +1

d = 0.919 L

co ordinate of this point is = L + d = 1.919 L

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do comment in case any doubt, will reply for sure.. Goodluck

Answer 2

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