Question

In the figure, E = 84.6 V, R - 9.23 2, R2 = 24.8 2, R3 = 35.3 2, and L - 1.64 H. Immediately after switch S is closed, what are (a) /1 and (b) 12? (Let currents in the indicated directions have positive values and currents in the opposite directions have negative values.) A long time later, what are (c) Just then, what are (e) /and (f) iz? A long time later, what are (9) /and (h)iz? and (d) 12? The switch is then reopened. pammy Units Units (a) Number (b) Number (c) Number (d) Number Units Units (e) Number Units (f) Number Units (9) Number (h) Number Units Units

Answer 1

> Solutions Initially cursent es through the inductor was zedo becoz of the absence of any active source (before Switching 4t means Inducty was Initially uncharged Inducted does not allow the Sudden change of the cassent through t o the situation of Current through the inductor will be ame after switching Just for little bit time dusation. → Circuito R = m = 0 Amp) 346V - T R =24.3-2 →Oben elements un i us=35.32 So; ezia (becoz of i=0 A Just after the switching) By applying KVL en Coop ④ , we geti i = 2 = 2.486 Amb a RtR₂) @ 1 = 2.486 AMP Ans lig= 20486 Amp | Ans L = 12 = 84.6.

> Circuit af het a long time switching: um 4 Buum 43 > By abhlying Nodal analysis at {=84-66 77 crew + Phyly Nodal analysis of R159-23.12 X 13=353-7 Nodê B, we get; Rz=2421 84.6-VB = VB + VB -> 9.23 24.8 353 (Short circuit 846 - Velit doment fully Charged States 9.23 9.23 > NB = 5 1 785 valt So; © i= 8406– 51705 >4= 3.55 Amp] Amblies 9.23 la= 59.49785 = Tia= 20098 Ampl. Ans → Vol -43 + elke tag ]

> Circuit Just after deopened the switch: 780425-3) bereits fiz= ve = 51.185 2 → 13 = 7:466 Amp ! © TT,=0 Amp / Ø la=-13 = -1•460Ampli - a ruzo Amp l Tha=0 Ampi for little bit duration, Inductor benares, like an current Saree element). N 25.2 Ans