Question

I need help solving this please!

QUESTION 3 You have pipetted a volume of water that has a mass of 0.978 g. The volume of the water is 0 978 L (liter) 0 978 μL (microliter) 978 mL (milliliter) 0.978 L (iter) Click Save and Submit to save and submit Click Save All Ansicers to sune all ansuers

Answer 1

given

mass of 0.978 g

here 1 gram = 0.001 ltr

0.978 gr = 0.001 x 0.978

= 0.000978 ltr

or

= 978 x 10^-6 ltr

= 978 $\mu$L ( micro liter )

second option is correct