(a)
Given, P(Y = 1) = p
=> P(Y = 0) = 1 - p
P[B | Y] = 0.9 - 0.7Y
Therefore,
P[B | Y = 0] = 0.9 - 0.7 * 0 = 0.9
P[B | Y = 1] = 0.9 - 0.7 = 0.2
By law of total probability,
P[B] = P[Y = 0] P[B | Y = 0] + P[Y = 1] P[B | Y = 1]
= (1 - p) 0.9 + p * 0.2 = 0.9 - 0.7p
By Bayes theorem,
P(Y = 1 | B) = P(B | Y = 1) * P(Y = 1) / P(B)
= 0.2p / (0.9 - 0.7p)
(b)
For less than 10% of college educated borrowers default,
P[ Y = 1 | B] < 0.1
0.2p / (0.9 - 0.7p) < 0.1
0.2p < 0.09 - 0.07p
0.27p < 0.09
p < 0.09/0.27
p < 1/3
Thus, p should be less than 1/3.
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