Question

Suppose a random sample of nequals=100100 measurements is selected from a population with mean muμ and...

Suppose a random sample of

nequals=100100

measurements is selected from a population with mean

muμ

and standard deviation

sigmaσ.

For each of the following values of

muμ

and

sigmaσ​,

give the values of

mu Subscript x overbarμx

and sigma Subscript x overbar Baseline .and σx.

a.

muμequals=5,

sigmaσequals=2

b.

muμequals=25​,

sigmaσequals=100

c.

muμequals=10

sigmaσequals=80

d.

muμequals=5​,

sigmaσequals=190

a.

mu Subscript x overbarμxequals=55

sigma Subscript x overbarσxequals=2.2

​(Type an integer or a​ decimal.)

Both of your answers are incorrect. For a sampling distribution x overbar comma x,

mu Subscript x overbar Baseline equals Upper E left parenthesis x overbar right parenthesis equals muμx=Ex=μ

and sigma Subscript x overbar Baseline equals sigma divided by StartRoot n EndRootσx=σ/n.

PLEASE LOOK AT THESE AGAIN AND HOPEFULLY GIVE THE CORRECT ANSWER.THANK YOU

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Answer #1

Sample size = n = 100

We have to find the mean and standard deviation of ar{x} for each of the following.

a)

mu = 5

sigma = 2

Mean of the ar{x} = mu = 5

The standard deviation of ar{x} = sigma/sqrt{n}=2/sqrt{100}=0.2

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b)

mu = 25

sigma = 100

Mean of the ar{x} = mu = 25

The standard deviation of ar{x} = o/v/n 100/V100 10

----------------------------------------------------------------------------------------------------------------------------------------------

c)

mu = 10

sigma = 80

Mean of the ar{x} = mu = 10

The standard deviation of ar{x} = sigma/sqrt{n}=80/sqrt{100}=8

----------------------------------------------------------------------------------------------------------------------------------------------

d)

mu = 5

sigma = 190

Mean of the ar{x} = mu =The standard

ard deviation of ar{x} = o/v/n-190/V100-19

----------------------------------------------------------------------------------------------------------------------------------------------

I think you will get your answer if any doubt regarding this question please comment.

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