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b. RELAB: Name: e at the beginning of lab. Write your answers in the space provided. Ise the solubility curve to help you ans

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Answer #1

Following is the - the complete Answer -&- Explanation: for the first four questions ( i.e. Question - 1 to Question - 4) , of the given:  Question Set..in.....typed format...

\RightarrowAnswer(s):

  1. question - 1:  The x- axis: goes from 0 oC to  100.0 oC. because, it is an aqueous solution.
  2. question - 2:  Potassium Iodide ( KI ), is most soluble substance at 10.0 oC...
  3. question - 3:  NaCl and KClO3  : have the same solubility, at 80.0 oC...
  4. question - 4:  The solubility of KNO3, changes most drastically, with increasing temperature. And, NaCl, shows the least amount of change in solubility: with increasing temperature.

\RightarrowExplanation:

Following is the complete: Explanation: for the above: Answers...

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\RightarrowQuestion - 1:

Since, we have the solvent: as water: and the given graph: along the y - axis: shows the aqueous solubility of different compounds, the : range of temperatures: along the x -axis: range from : 0.0 oC  ( i.e. the melting point of water ), and 100.0 oC ( i.e. the boiling point of water ), i.e. the range of temperature, within which, a compound , can get and remain dissolved in liquid water. Therefore: the above is the reason: for which: the x-axis: of the graph: shows, temperatures: from 0.0 oC to 100.0 oC, only !

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\RightarrowQuestion - 2:

As we can see, from the graph: at 10.0 oC , potassium iodide ( KI ) , shows the solubility of about: 138 g solute / 100 g of H2O  , ( i.e. approximately: 138 grams of potassium iodide, remains dissolved in about 100 grams of solvent, i.e. water , at 10.0 oC ). The above is the reason: our answer: would be: KI , which has the maximum solubility, at 10.0 oC, among the other given compounds.

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\RightarrowQuestion - 3:

As we can see, from the given: graph: at  80.0 oC, both : NaCl, and KClO3, show the same solubility of : approximately: 40.0 g solute / 100 g of solvent ( i.e. H2O ) ...

Thus, our answer: will be: NaCl and KClO3.... which two compounds share approximately, the same solubility: at 80.0 oC..

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\RightarrowQuestion - 4:

As we can see, from the given: graph: the slope of the increasing solubility : of  KNO3is the highest, and as we can see, the solubility: of NaCl, doesn't change significantly, with increasing temperature... Therefore: our answers : will be: KNO3, and NaCl , respectively...

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