What is the pH of a solution that contains 0.50 MH3PO4 and 0.89 M NaH2PO4? The...

Question

Question

Answer 1

Answer #1

given

Concentration of H₃PO₄ = 0.50 M

concentration of NaH₂PO₄ = 0.89 M

Equilibrium constant k_a = 7.5 x10^-3

for acid buffer,

pH = pK_a + log(salt/acid)

where pK_a is logarithmic value of K_a

salt and acid are molar concentration of them respectively

here salt is NaH₂PO₄ and acid is H₃PO₄

pH = -log(7.5 x 10^-3) +log (0.89/0.50)

pH = 2.12 +0.25

pH = 2.37

Answer 2

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