Question

please show the work on how to solve as im trung to get the hang of it

part 1

What is the percent ionization of a 0.00600 M solution of HCO2H? The K, is 1.8x10-4 Multiple tries are permitted; however, 20% (1/5) point will be deducted for each incorrect response.

part 2

part 3

part 4

part 5

Answer 1

kindly post different questions separately. please rate

Part 1 ICE Table concentration CMI HCOOH (agl e HCoo- (aq) + H+ (aq) o 0.00600 +0 tox 0.00600 . Ka= [HCOO -] CHA} [HOOGHI 118810-4 = x x IC 10.0060o-DC - Soluing oc2 + 118.810-4% - 1008 x 10-6 = 0 this quadratic equation i we get volw of se gc = -b t J 62-49c. 29 b= 118 x 10-4 ca - 1:08810-6 x = 9.51 x 10-4M 9.51 X 10 -4 M Dissocrated concentration of HOOOH = 36 = initial concentration of HCOOH = 0.00600 M X loo Percent lonization of HCOOH initiai concentration 9,51810-4 x100 0.00600 = 15,85 4 Answer