mass(C7H5O2Na)= 1.9 g
use:
number of mol of C7H5O2Na,
n = mass of C7H5O2Na/molar mass of C7H5O2Na
=(1.9 g)/(1.44*10^2 g/mol)
= 1.319*10^-2 mol
volume , V = 20 mL
= 2*10^-2 L
use:
Molarity,
M = number of mol / volume in L
= 1.319*10^-2/2*10^-2
= 0.6597 M
Answer: 0.66 M
6. You made a solution of sodium benzoate by dissolving 1.9gm of sodium benzoate in 20ml...
please answer all three 6. You made a solution of sodium benzoate by dissolving 1.9gm of sodium benzoate in 20ml of distilled water. Calculate its molarity (MW of sodium Benzoate 144gm) 7. You added 2ml of 3M HCL to the above benzoate solution and tested the pH which was 3.1. Given that the PKA of benzoic acid is 4.1, what are the ratios of sodium benzoate of benzoic acid in your reaction? 8. In the above experiment, what is the...
You made a solution of sodium benzoate by dissolving 1.9 grams of sodium benzoate in 20 mL of distilled water. Calculate its molarity. (MW of sodium benzoate is 144 g)
You add 2 mL of 3M HCl to the above benzoate solution and tested the pH was 3.1. Given that the pka of benzoic acid is 4.1, what are the ratios of sodium benzoate to benzoic acid in the reaction? You made a solution of sodium benzoate by dissolving 1.9 grams of sodium benzoate in 20 mL of distilled water. Calculate its molarity. (MW of sodium benzoate is 144 g)
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