Question

Need Help With the second part!

Checkpoint: 1-D Kinematics Deadline: 100% until Monday, January 28 at 8:00 AM Rolling down a ramp ? 2 Att-0 a ball, initially at rest, starts to roll down a ramp with constant acceleration. You notice it moves 1 foot between t-0 seconds and t 1 second 1) How far does it move between t1 second and t-2 seconds? 1 foot 2 feet 3 feet 4 feet 6 feet Submit You currently have 1 submissions for this question. Only 5 submission are allowed You can make 4 more submissions for this question Your submissions: C Submitted: Saturday, January 26 at 6:04 PM Feedback: Feedback will be available after 8:00 AM on Monday, January 28 (Survey Question) 2) Briefly explain your answer to the previous question Submit You currently have 0 submissions for this question. Only 5 submission are allowed You can make 5 more submissions for this questiorn

Answer 1

2) The initial velocity is 0 m/s as the ball starts from rest. The distance travelled by the ball is s=1 ft. The time taken by the ball to travel this distance is t=1 s. Now, acceleration of the ball can be calculated as follows: s=ut+- ar 1 ft = 0() +2a(15) a=2 ft/s? Now, The distance travelled by the ball between 0 s to 2 s can be calculated as follows: s'=0(e)+L(2 ft's*)(25) s'= 4 ft Thus, the distance travelled between time t=1s to 2 s can be calculated by subtracting the distance covered by ball in initial 1 s, from the distance travelled by the ball in 2 seconds. So, d = 4 ft-1 ft = 3 ft 1) 3 feet