Question

STOICHIOMETRY INVOLVING SOLIDS, LIQUIDS, AND GASES 1. 16.50 g of glucose, C6H12O6 was burned in the presence of excess oxygen, calculate the volume of CO2(g) that is produced at STP? CH120e(s) + 6O2(g) 6CO2(g) + 6H2O(g) 16.5g/1 mol CGHI2O 16 mol CO2 | 22.4L = 12.312 1180.156 C6H12 Ool Imol C6H12O6 mol CO2 What volume of 0.250 M HCl is required to completely react with 0.350 g of Na2CO3? Na2CO3(s) + 2HCl(aq) + 2NaCl(aq) + H2O(0) + CO2(g) (3.) Calcium carbonate decomposes at high temperatures to give calcium oxide and carbon dioxide. What volume of CO2 will be collected at 950 torr and 500°C, when 75.0 g of CaCO3 react? CaCO3(s) CaO(s) + CO2(9) 4. How many mL of 0.250 M KMnO4 are needed to react with 3.36 g of FeSO4? 10 FeSO4 + 2 KMnO4 + 8 H2SO4 → 5 Fe2(SO4)3 + 2 MnSO4 + 8H20 + K2SO4 (5) Potassium chlorate reacts with hydrochloric acid to produce chlorine gas. What mass of KCIO3 is needed to make 4.50 L of chlorine at 2.35 atm and 37.0°C? KCIO3(g) + 6HCl(aq) → KCl(aq) + 3Cl2(g) + 3H2O(1)

Answer 1

Moles of glucose 16.5 - = To mass of glucose = 16.50g Molar mass of glucose = 180 156 g/mol = mass molar mass - 180.156 =0.091 moles 0.091 mole C6H12O6 (5) + 602 19) 6CO2(g) + 6H2O ig) 6 moles of coa formed from a mole of " GH12O6 0.091 moles of Colla oo forens (6 x 0. 091) moles = 0.546 of cor At STP 1 mole O2 = 22.4 L 0.546 mole of co2 = 22.4 X0.546 Volume of cor produced = 12.23 L 20 moles of Nas CO₂ = mot mass - 0.350 g molar mass 105.98 g/mol = 0.0033 moles: 1 mole Nag CO₂ - 2 moles of ruce 0.003 3 mole Na co z 2x0.0033 moles of rice Moles of rice reacted =0.0066 moles - 00066 moles Volume 0250 Molarity - 0.250 = 0.0066 Volume Volume of rece = 0.0264 L)