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and a 51.6 m cliff that 1.5 s apart and s that they cause a single splash. The first stone has an initial velocity of 1.95 m/s. How long after release of the first stone do the two stones hit the water? 3.05s Previous Tries What is the initial velocty of the second stone if the two stones hit simultaniously? 2132m/s Submit Answer Tries 1/8 Previous Tries What is the speed of each stone when it hits the water, Enter the slower speed first Submit Answer Tries o/8
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distance covered by the first stone in timet-h v=1.95 ; g-9.8 ;h-51.6 we plug the values in hand while using the quadratic relation give us t-3.052 sec if the second stonecover the same distance in time,t-3.05s-1.5s-1.55sec initital velocity of the sec ond stone v t-1.55 sec ; g-9.8;h-51.6m distance travelled by the second stone h we plug the values in hand while using the relation give us v=25.70 m/s speed of the sec ond stone when it hit the water = 40.89

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