Question

Part C The absorbance of a cationieron) sample solution was measured in a spectrophotometer, but the instrument returned an error because the absorbance was too high. The sample was then diluted by using a pipette to take 100.0 L of the sample and injecting it into a cuvette already containing 2.00 mL of water total volume is 200 ml + 100.0 L). The absorbance value of the diluted solution corresponded to a concentration of 7.84x10-6 M. What was the concentration of the original solution? Express the concentration to three significant figures with the appropriate units. View Available Hints) original concentration of Pet V alue Units Submit Provide Feedback Next >

Answer 1

Final concentration - 7.84 X100M (C2) Volume = 2.00ml + 100 ML (V2) - 2 ml + 0.1 ml = 2.10 ml 0.10 ml Initial concentration (G) = ? Initial Volume (V.) = 100 ML = Using dilution formula, C, V = C₂ 1/2 C = CzV₂ = 7.84 x 10-6 M x 2.10 ml 0.1 ml a = 7.64 1.65 x10-4 MI