For enzymes in which the slowest (rate-limiting) step is the reaction:
K2
ES → E+P
Km becomes equivalent to:
A) kcat.
B) the [S] where V0 = Vmax.
C) the dissociation constant, Kd, for the ES complex.
D) the maximal velocity.
E) the turnover number.
The answer is C), could you please explain?
thank you very much,hope this will helpful for you,good luck from my side
For enzymes in which the slowest (rate-limiting) step is the reaction: K2 ES → E+P Km...
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