Question

A negatively charged oil drop whose mass is 10-15 kg and whose charge is -6.4 10-19...

A negatively charged oil drop whose mass is 10-15 kg and whose charge is -6.4 10-19 Coulombs remains stationary under the influence of the Earth’s gravitational field and a uniform external electric field made by two oppositely-charged parallel plates (see diagram below). Ignore the influence of Earth’s electric field on the oil drop.

  1. Determine the magnitude and direction of the net electric field created by the plates (not the electric field of the oil drop !). Explain completely how you determined the direction of the field - you’ll need to explain how you apply the positive test charge rule as part of your explanation. Yes this is a net force problem.

  2. On the diagram above, draw the electric field lines created by the plates – make your field lines clearly show that the magnitude and direction of the electric field are constant. Make sure your diagram is consistent with the information given in the problem statement.

  3. How many excess electrons does the drop have ?

  4. If the charge of the oil drop were doubled, but everything else in the problem remained the same, what would happen to the oil drop ? Determine the magnitude and direction of the oil drop’s acceleration (if any) for this situation.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

STATIOPAR 101508 NEGATIVE PLATE HENCE oTom PLE IS AND E-FIELD LIUES 15 2 (6, u K to1リ@s3xrol) _lo C98 l o

I will be glad to see your comment if you have any query and thumb up if you are satisfied. Thanks...

Add a comment
Know the answer?
Add Answer to:
A negatively charged oil drop whose mass is 10-15 kg and whose charge is -6.4 10-19...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • In an oil-drop experiment a negatively charged oil drop has a mass of 3.0 x 10-15...

    In an oil-drop experiment a negatively charged oil drop has a mass of 3.0 x 10-15 kg and is held at rest between two parallel plates separated by a distance of 2.0 cm. The potential difference between the plates is 460 V. a) On the diagram below, show all the applied forces on the drop. Do not include the buoyant force of the air on the oil drop. b) What is the strength of the electric field between the plates?...

  • 1. An oil drop with a mass of 2.45 g is suspended between two Problem 01...

    1. An oil drop with a mass of 2.45 g is suspended between two Problem 01 oppositely-charged plates that are 10.00 cm apart and have a potential-- difference of 6000 V as shown in the diagram to the right. a.) Show the direction of the electric field on the diagram. b.) What is the magnitude of the electric field? c.) What is the force due to gravity acting on the oil drop? d.) What is the charge on the oil...

  • A positively charged oil drop has a mass of 2.76 * 10^-14 kg. It is suspended...

    A positively charged oil drop has a mass of 2.76 * 10^-14 kg. It is suspended in an electric field of 4.2 * 10^5 N/C between 2 parallel plates with a capacitance of 2 uf spaced 3 cm apart. a.) What is the charge on the drop? b.) How many electrons is the drop missing? c.) What is the electric potential across the plates? d.) How much charge is stored on each plate? e.) How much energy is stored in...

  • In 1909, Robert Millikan was the first to find the charge of an electron in his...

    In 1909, Robert Millikan was the first to find the charge of an electron in his now-famous oil-drop experiment. In that experiment tiny oil drops were sprayed into a uniform electric field between a horizontal pair of oppositely charged plates. The drops were observed with a magnifying eyepiece, and the electric field was adjusted so that the electric force on some negatively charged oil drops was just sufficient to balance their weight. Millikan accurately measured the charges on many oil...

  • In the famous Millikan oil-drop experiment, tiny spherical droplets of oil are sprayed into a uniform...

    In the famous Millikan oil-drop experiment, tiny spherical droplets of oil are sprayed into a uniform vertical electric field. The drops get a very small charge (just a few electrons) due to friction with the atomizer as they are sprayed. The field is adjusted until the drop (which is viewed through a small telescope) is just balanced against gravity and therefore remains stationary. Using the measured value of the electric field, we can calculate the charge on the drop and...

  • with diagram if possible 0.0200 mx Figure 16-33 Problem 86 In the famous Millikan oil-drop experiment,...

    with diagram if possible 0.0200 mx Figure 16-33 Problem 86 In the famous Millikan oil-drop experiment, tiny cal droplets of oil are sprayed into a uniform vertical electric field. The drops get a very small charge (just a few elec trons) due to friction with the atomizer as they are sprayed. The field is adjusted until the drop (which is viewed through a small telescope) is just balanced against gravity and there- fore remains stationary. Using the measured value of...

  • In the famous Millikan oil-drop experiment, tiny spherical droplets of oil are sprayed into a uniform...

    In the famous Millikan oil-drop experiment, tiny spherical droplets of oil are sprayed into a uniform vertical electric field. The drops get a very small charge (just a few electrons) due to friction with the atomizer as they are sprayed. The field is adjusted until the drop (which is viewed through a small telescope) is just balanced against gravity and therefore remains stationary. Using the measured value of the electric field, we can calculate the charge on the drop and...

  • 1. A. An oil drop has a mass m. The drop is falling at a terminal...

    1. A. An oil drop has a mass m. The drop is falling at a terminal speed vfall. Draw a free body diagram for the drop. Write the Newton’s Second law equation for the drop. Find the expression for the value of k in terms of the mass of the drop (m), the terminal speed (vfall), and g. B. The oil drop from C has a charge +q. It is now in a uniform electric field that points upward with...

  • A negatively charged particle, with charge q = 5.10×10−6 C, has a velocity of 416 m/s...

    A negatively charged particle, with charge q = 5.10×10−6 C, has a velocity of 416 m/s in the positive x-direction, moves into a region with a magnetic field and an electric field. The magnetic field, has a magnitude of 1.50 T, and is pointing in the positive y-direction. The electric field, has a magnitude of 4.00×103 N/C, and points in the positive z-direction. What is the value of the net force on the charged particle? A. 2.36×10−2 N, negative z-direction...

  • What is the answer to part B, and what formula should be used? t A Proton...

    What is the answer to part B, and what formula should be used? t A Proton between Oppositely Charged Plates 4 of 10 > Constants Part A A uniform electric field exists in the region between two oppositely charged parallel plates 1.70 cm apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.54x10-6 s Find the magnitude of the electric field Use...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT