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The average bill in a restaurant for 49 customers is found to be $30.90, with a...

The average bill in a restaurant for 49 customers is found to be $30.90, with a standard deviation of $3.20. Construct a 99% confidence interval for the average bill.

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//kte have te fina ss % conf.intervS) 2 乙一、乙 O-99 30-90-(2-582-3.20 upper limit 드 3o.go.tc2.53) 3.20一 3o. 9o+1.179therefore 99% confidence interval for average bill (29.7206, 30.0794)

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