Question

IReview Part A The figure (Figure 1)shows two different processes by which 66 mol of gas move from state 1 to state 2. The dashed line is an isotherm What is the temperature of the isothermal process? Express your answer to two significant figures and include the appropriate units. Figure 1 of 1> TValue Units P (kPa) Submit Request Answer 200 ▼ Part B Isotherm 100 What maximum temperature is reached along the straight-line process? Express your answer to two significant figures and include the appropriate units V (m3) | Tmax = 1 Value Units

Answer 1

Solution:

A) At point 1

T = P * V / n*R

=> T = 100 *1000* 2 / 66 * 8.314

=> T = 364.48 K

=> T = 360 K ( in two significant figures)

B) Using,

P = nRT/V = mV + c (equation of the straight line)

=> T = (mV² + cV) / nR............(i)

=> for maximum temperature dV/dT should be zero ,

=> after solving , 2mV + c = 0

=> V = 1.5 m^3

Using equation 1 we get

=> T = 410 K ( in two significant figures)