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0.0055 mol of gas undergoes the process 1 rightarr

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Answer #1

Using Ideal Gas eq,
p*v = nRT
As you know, p1 = 1 atm
v1 = 100 cm^3
n = 0.0055 mol

p1*v1 = n*RT1
1 * 101325 * 100 * 10^-6 = 0.0055 * 8.314 * T1
T1 = 221.6 K

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0.0055 mol of gas undergoes the process 1 rightarrow 2 rightarrow 3 shown in the figure(Figure...
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