0.0044 mol of gas undergoes the process shown in (Figure 1). What is the initial temperature...
0.0044 mol of gas undergoes the process shown in (Figure 1).
What is the initial temperature in degrees C?
What is the final temperature in degrees C?
Homework Answers
no. of moles of gas = 4.4*10^-3 mol
P1 = 3 atm = 3.03*10^5 Pa
P2 = 1 atm = 1.01*10^5 Pa
V = 200 cm^3 = 2*10^-4 m^3
R = 8.314
Using ideal gas law:
P1*V = nRT1
T1 = P1*V/nR
T1 = 3.03*10^5*2*10^-4/(4.4*10^-3*8.314) = 1656.57 K
T1 = 1656.57 - 273.15 = 1383.42 C
final temperature of gas will be
T2 = P2*V/nR
T2 = 1.01*10^5*2*10^-4/(4.4*10^-3*8.314) = 552.19 K
T2 = 552.19 - 273.15 = 279.04 C
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