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The figure shows 0.32 mol of gas that undergoes the process from 1 to 2. The...

The figure shows 0.32 mol of gas that undergoes the process from 1 to 2. The gas then undergoes an isochoric heating from point 2 until the pressure is restored to the value it had in point 1. What is the final temperature of the gas? Note: 1 atm = 101 kPa

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Answer #1

PV = nRT

T = nR/PV = .32*.0821/3*3 = .0029K

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