Electrolysis equation is:
Ag1+ + 1e- ------> Ag
1 mol of Ag requires 1 mol of electron
1 mol of electron = 96485 C
So,1 mol of Ag requires 96485 C
let us calculate mol of element deposited:
molar mass of Ag = 107.87 g/mol
use:
number of mol of Ag, n = mass of Ag/molar mass of Ag
= 28.3/107.87
= 0.2623 mol
total charge = mol of element deposited * charge required for 1 mol
= 0.2623*9.649*10^4
= 2.531*10^4 C
use:
time = Q/i
= 2.531*10^4/2
= 1.265*10^4 seconds
= 1.265*10^4/3600 hr
= 3.515 hr
Answer: 3.5 hr
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