Homework Answers
E = E' - RT lnQ/nF .....(1)
E = E' - X logQ/n .....(2)
When we conver ln to log, we multiply by 2.303
Thus, equation (1) can be written as;
E = E' - 2.303*RT logQ/nF ....(3)
Comparing equation (2) and (3)
X = 2.303RT/F
R is gas constant with value 8.314 J/mol K
Temperature in Kelvin i.e. 25°C = 273+25 = 298K
Faraday constant (F) = 96500 Coulombs
X = 2.303 * 8.314 * (25+273) / 96500
X = 0.0592 Volts
X = 0.0592 V ....Answer
Let me know if any doubts.
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