Question

I'm struggling a bit in physics, if anyone can help me out soon, that'd be great!!

3. In Lab #05 - Free Fall Motion, the time and position of a freely falling object are measured. The results are shown in Table 3. Assuming the position equation has the form of Y ) - Ata + Bt + C, (a) determine the function Y(t) by using the given data in Table 3. (b) Calculate the gravitational acceleration, g, and initial velocity. V. from the coefficients of y(t). (©) Assuming the known value of 9known = 9.8 m/s2, calculate the percent difference for g. Time (sec) Distance (m) 4 15.6 66.4 Table 3.

Answer 1

- - - 24-1-4- - - - - - - first first o - - - - Given Data - Time (sec) 1 Distance (m) Second - ĭ---- isa Thind --3- 766.4 (a.) y(t) = At" + B+ c by first data ->.4. - A(0)2 + B(0)+c TC=41 -0 by second data => 15,6 = ACU?+ B(1) + c => A+B+C = 15.61-® by third data => 66.4 = A(3)? + B(3) + => 9A + 3B + C = 66.41-3 by © ©,3 A = 4.6 m/s2 B = 7 m/s So y(t) = 4.6ť?+7+41 C = 4 m

(b.) by s=ut + lat? sx = ut - Igt? Y()-C = At? + Bt by comparing the equation 29 =A 9=2A lg = 9.2m/s²7

(C) % difference I known - g 2 x 100% I known 9.8-9.2 x 100 % 9 = 9.8 = 6.122%.