Kererences CHEMWORK A 50.0 mL sample of 0.0495 MAgNO3(aq) is added to 50.0 mL of 0.100...

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Question

Answer 1

Answer #1

AgNO3= 50.0ml of 0.0495M

NaIO3 = 50.0mL of 0.100M

after mixing

concentration of NaIO3 = 0.100 x 50.0 / 50.0+50.0 = 0.05M

NaIO3 ---------------- Na+ + IO3-

Concentration of IO3- = 0.05M

Ksp = 3.17x10^-8

AgNO3(aq) + NaIO3(aq) ---------------- AgIO3(s) + NaNO3(aq)

AgIO3(s) --------------- Ag+(aq) + IO3-(aq)

Ksp = [Ag+][IO3-]

3.17 x10^-8 = [Ag+] x 0.05

[Ag+] = 63.4 x10^-8M

[Ag+] = 6.34 x10^-7M

Concentration of Ag+ = 6.34 x10^-7M = 6.34 x10^-7 mol/L

Answer 2

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