If 37.5 mL of 0.100 M NaOH is added to 10.0 mL of 0.100 M CH3COOH, what will be the pH of the resulting solution?
CH3COOH(aq)+OH−(aq)→CH3CO−2(aq)+H2O(l)
If 37.5 mL of 0.100 M NaOH is added to 10.0 mL of 0.100 M CH3COOH,...
500.0 mL of 0.100 M NaOH is added to 595 mL of 0.250 M weak acid (Kg = 4.90 105). What is the pH of the resulting buffer? HA(aq) + OH(aq) → H,O(l) + A+ (aq) Number pH =
What change in pH should be observed if 10.0 mL of 0.100 M NaOH is added to 100 mL of a buffer that is 0.100 M in CH3COOH and 0.100 M in NaCH3CO2? Ka for acetic acid is 1.8 x 10-5.
A volume of 500.0 mL of 0.100 M NaOH is added to 545 mL of 0.200 M weak acid (K, 7.44 x 10). What is the pH of the resulting buffer? HA(aq) + OH (aq) H,O)+A (aq) 4.208 PH
A volume of 50.0 mL of 0.100 M CH3COOH(aq) is titrated with 0.100 M NaOH(aq). What is the pH at the equivalence point? (Ka for CH3COOH = 1.8 × 10–5) (1) 7 (2) 5.28 (3) 8.72 (4) 6.34 (5) 4.15
Assume a titration with 0.100 M NaOH titrant and 25.00 mL of a 0.0800 M CH3COOH analyte. How many mL of NaOH is required to reach the equivalence point? Assume a titration with 0.100 M NaOH titrant and 25.00 mL of a 0.0800 M CH3COOH analyte. What will the initial pH of the analyte be if 0.00 mL of NaOH is added?
A volume of 500.0 mL of 0.150 M NaOH is added to 525 mL of 0.250 M weak acid (?a=4.43×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) pH=
A volume of 500.0 mL of 0.140 M NaOH is added to 625 mL of 0.200 M weak acid (?a=6.07×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) pH =
A volume of 500.0 mL of 0.170 M NaOH is added to 545 mL of 0.200 M weak acid (Ka=6.26×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) pH??
500.0 mL of 0.110 M NaOH is added to 585 mL of 0.250 M weak acid (Ka = 2.27 x 10-5 M). What is the pH of the resulting buffer? HA(aq) + OH(aq) - H2O(l) + A-(aq) pH =
A volume of 500.0 mL of 0.120 M NaOH is added to 605 mL of 0.250 M weak acid (K, = 7.89 x 10-). What is the pH of the resulting buffer? HA(aq) + OH(aq) → H2O(l) + A™(aq) pH II