Question

Exercise 4 Consider ariom (1.4). It is often described as a continuity ariom. Explain why it is described that way. (Hint: Notice that if a 1 and b 0 (which are not permissible choices of a and b), then the conclusion simply repeats the assumption.)(1.4) If a a a, then there exist a and ό in (0,1) such that aa (1- a)a a ba +(1 -b)a.

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Answer #1

Considering the values of a,b in (0,1) there is possibility of an arrays of value of a such that

aα+(1-a)α''≻α'

Similarly there is other set of values of b fro (0,1) such that

α'≻bα+(1-b)α"

It just represents the syntax of Convex hull where U(aα+(1-a)α'')>U(α') and on the other hand we have U(α')>U(bα+(1-b)α'')

This axiom is generally used in expected utility settings

For an instance assume

α= Visiting Paris through Air travels ; α''=Death while travelling due to terrorist attack over a same plane

α'= Watching Paris on Video at home

This means if we place as low possible probability on Death we will always prefer to go to Paris that is

aα+(1-a)α''≻α' but as soon as we weigh incident of death heavily we start to opt α'≻bα+(1-b)α"

This is the layman meaning of this axiom

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