1)
Given:
pH = 13.00
use:
pH = -log [H3O+]
13.00 = -log [H3O+]
[H3O+] = 1.0*10^-13 M
Answer: 1.0*10^-13 M
2)
Given:
[H3O+] = 1.0*10^-13 M
use:
[OH-] = Kw/[H3O+]
Kw is dissociation constant of water whose value is 1.0*10^-14 at 25 oC
[OH-] = (1.0*10^-14)/[H3O+]
[OH-] = (1.0*10^-14)/(1.0*10^-13)
[OH-] = 0.10 M
Answer: 1.0*10^-1 M
Question 1 (of 15) value 1.00 points 3 attempts left Check my work Be sure to...
3 attempts left Check my work Be sure to answer all parts. Report prot For an aqueous solution with a concentration of 1.0 10 M, calculate the concentration of OH. Hint X10 M Enter your answer in scientific notation. Solution Guided Soluti < Prex 1123 Next > e to search DOLL
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