Homework Answers
Given enthalpy of combustion of benzoic acid is 3227kj/mole.
I.e 122 grams of benzoic acid upon combustion produces 3227 kj of heat energy.
1.0 gram of benzoic acid upon combustion produces1.0*3227/122 = 25.409 kj
Heat gained by water = mst = ms(t2-t1)
where m is mass of water and s is specific heat of water.
25.409*1000 = 500*4.184*t
The change in temperature, t = 12.15 degree
Celsius.
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