2. Class intva Relative frequen 0 to < 10 10 to <20 20 to <30 30to<40...

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Answer 1

Answer #1

class width=difference between consecutive lower or upper class limits =				10
n=total frequency =				100
L_me lower limit of median interval, c-class width,n-total frequency=				10
f_cum. Is cumulative frequency till previous interval to median =				10
f_me is frequency of median interval =				50

median=	L_me+c*(n/2-f_cum.)/f_me	=	18.00

option D is correct

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Answer 2

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