Question

help please in detail with algebraic breakdown

6. Consider a spring with spring constant 13 N/m. This spring is mounted to be stretched horizontally and a 6.5 kg mass is attached to it. This mass is then pulled back from its equilibrium position, released, and allowed to oscillate horizontally along a frictionless plane. When the mass is at a displacement of 0.30 m, its velocity is observed to be 0.80 m/s. Using energy conservation, determine the mass' velocity when its position is a) zero, b) 0.20 m, c) 0,40 m, d) 0.60 m, and e) 0.80 m. Hint: Use the given displacement and velocity as your initial event.

Answer 1

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bo th we gel equaling X6SxV 2.665 2 (q) Enengy at x-oim) will be PESering tk-Egm kx mv2 amd 3 equaling eqvalie 2.665 13x(0-2)t 65xv2-65x2 6-Su 2.65X2- 3x-2) XO 2 (c) Similanlg, Enengy a (x=o4m) X1SxG equaling quai and x13x-+) s v 2-605 6SXV 6.70 m/S cs Scanned with CamScanner

(x-06m) d) Eneryy mv2 2 equahing equaon 13xlo )65x v 2-665 and O 31m/s al (x08m) e) nerjy kxm 2 equaling equaon and Lx 13 x 8 X6SK V 2-665 2 0 67 MIS towards pesitien mean Plea se like eu ind this soluhen helppul Scanned with CamSaner